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[Prev][Next][Index][Thread] Re: another version of frequency formula
To: tesla@grendel.objinc.com
Subject: Re: another version of frequency formula
From: EDHARRIS@MPS.OHIO-STATE.EDU
Date: Tue, 16 Jan 1996 10:39:51 -0500 (EST)
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The above formula does not take into account the coiling of the wire. Written in similar terms to the above, the formula I posted becomes:
c (1/5)
F = ------------------------ x (5/4) x (H/D)
4 x length of winding
c=speed of light
H=height of coil
D=diameter of coil
Nothing special. Just highlights the difference due to coiling the wire. For an H/D=10, the two forms differ only by a factor of 2. SOrry to beat a dead horse.
The length of wire as measured in what units? Inches, feet, meters ? Jim Leonard
---------------------------------- Jim, The one nice feature of the above formula is that you can use whatever units you want as long as they are consistent. For H and D all you need is the ratio which of course is unitless. If you choose the speed of light as c=3x10^8 meters/sec, then choose the length of the winding to be in meters so that the frequency will come out in Hz=1/sec. Alternately, you could choose the length of the winding in miles and c=186,000 miles/sec and still get the frequency in Hz. Eg. as Mark B. reported, his giant coil has the followinf dimensions: H=11ft
186,000 mile/sec (1/5)
F= -------------------- x (5/4) x (11ft/4ft)
4 x 1 mile
F= 71000 Hz
This is close to the self resonant (no top electrode) frequency he reported (correct me if wrong M). As I said before, it works well on all the coils I have made as well as all the coils Malcolm so gernerously reported on. -Ed Harris
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